Algebra Word Problem Solver

Solves Basic Math, PreAlgebra, and Algebra Word Problems Step-by-Step

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Solved Investment Word Problem

What You Enter
A total of $11,000 was invested. Part was invested at 4%, and the rest was invested at 7%. If the investments earn $680 per year, how much was invested at each rate?








What You Get
Let x = Amount Invested at 4%
Let y = Amount Invested at 7%

Amount Invested = $11,000
Total Income = $680
x + y = 11000
x = 11000 - y
0.04x +0.07y = 680
4x +7y = 68000
4(11000 - y) +7y = 68000
44000 - 4y +7y = 68000
3y = 24000
y = $8,000 Invested at 7%
x = 11000 - 8000
x = $3,000 Invested at 4%