| Find three consecuive odd integers such that if 4 times the second is added to 3 times the third, the result will be 27 times the first. |
Find SECOND Find FIRST Find THIRD Let S=SECOND Let F=FIRST Let T=THIRD Given S=F+2 Given T=F+4 Given 4S+3T=27F 4S+3(F+4)=27F Comment: Substitute F+4 for S in 4S+3T=27F 4(F+2)+3(F+4)=27F Comment: Substitute F+2 for T in 4S+3(F+4)=27F 4F+8+3F+12=27F -20F+8+12=0 Step F=1 Comment Simplify Solution F=1 Solution S=3 Substitute F=1 into S=F+2 Solution T=5 Substitute F=1 into T=F+4 End |