Algebra Word Problem Solver

If d varies directly as the square of t, and d = 11 when t = 3, find d when t = 6. 
 
 D = kT²    Direct Variation Statement
 
 11 = k * 3²          //  D = 11 WHEN T = 3 . Substitute values.
 
      11                                      
 k =  ---      //  Constant of Proportionality
       3²                             
 
      11                                      
 k =  ---      //  Constant of Proportionality
       9                                      
 
      11                                  
 D =  ---T²       //  D as a Function of  
       9                                  
 
 D = (11 / 9 ) 6²       //  T = 6 . Substitute value.
 
 D = (396 / 9 )       //  D WHEN T = 6 
 
 D = 44          //  D WHEN T = 6